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Binary Exponentiation → Read more...
Given two numbers $a$ and $n$ finding $a^n$ involves doing $n$ multiplications of $a$, however, it’s possible to do this in $log(n)$ operations by using binary exponentiation.
There's a total of 1 articles.
Given two numbers $a$ and $n$ finding $a^n$ involves doing $n$ multiplications of $a$, however, it’s possible to do this in $log(n)$ operations by using binary exponentiation.